How to place scale action line in center of area to be scaled?

[pentool]

Hi,

If I have a circular area which I want to scale down to create an edge loop, I Ctrl click the circle (polygroup) to mask off the area I want to scale. At this point I click in the middle of the circle to place the transform line. However, it is difficult to find the exact center of the area. If I don’t place the transpose line in the dead center, the scaling operation will be a tad offset to where the transpose line is.

Is there a way to place the transform line to the dead center of the (circular) area I want to scale?

Thanks.

[Doug_Jones]

http://docs.pixologic.com/user-guide/3d-modeling/posing-your-model/transpose/action-line/

[pentool]

I’ve actually seen that just before posting the question. But what I wanted to know if there’s a way to automatically center the action line to the center of a selection? I don’t want to just eyeball it. In the screenshot, I want to place the action line in the dead center of the selection so I can scale it precisely. The document only talks about how can I eyeball it by manually placing the action line. I was looking for a sort of automatic, precise way.

[Spyndel]

If the area in question is symmetrical along a primary axis, hide all but the target area, then with local symmetry activated, turn on X and Z, Y and Z, or X and Y symmetry depending on the facing, enter transpose mode and place the transpose anchor where the dots converge. Then unhide the mesh and perform your transpose operation.

[pentool]

That’s brilliant, thanks Spyndel!

[Doug_Jones]

There’s some settings for it too. http://docs.pixologic.com/reference-guide/preferences/transpose/